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This math problem is the longest.
Arithmetic method:

1956 ÷ (85+65) =1956 ÷150 =13.04 (hours)

Equation method:

Suppose two cars meet in x hours, then

(85+65)x= 1956

150x= 1956

x= 13.04

So, 13.04 hours later, the two cars met.

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