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Third grade math problems online, etc.
Solution: (1) If there are x middle-sized corners, there are 30-X small corners.

80X+30(30-X)≤ 1900

50X≤ 1000

X≤20

50X+60(30-X)≤ 1620

- 10X≤- 180

X≥ 18

It can be seen that there are three schemes: 18≤X≤20 and * * *.

Scheme 1: medium-sized corner 18 and small corner 12.

Scheme 2: medium-sized corner 19 and small corner 1 1.

Scheme 3: There are 20 middle-sized corners and 20 small corners 10.

(2) Scheme 1:18 * 860+12 * 570 = 22,320 yuan.

Scheme 2:19 * 860+1* 570 = 22610 yuan.

Option 3: 20 * 860+10 * 570 = 22,900 yuan.

It can be seen that the first scheme has the lowest cost, and the lowest cost is 22,320 yuan.