The other branch of the 1. image must be in the fourth quadrant, and this branch image and the image in the second quadrant are symmetrical about the origin. Because the image is in the second and fourth quadrants, n+7.

2. Because the image of this function is monotonically increasing in the second quadrant and the fourth quadrant, that is, the image of these two quadrants increases with the increase of x, so:

What time? a & lta 1 & lt； 0? What time? b & ltb 1

What time? 0<a< when a 1,? b & ltb 1

What time? A<0< when a 1,? b & gtb 1

Complete the solution