When m=0, f (x) =-6.
When-2 < = m <; 0,x2-x+ 1 >; 0, so f (x) < 0;
When 0
x^2-x+ 1<; 6/2
(x-2)(x+ 1)& lt; 0,- 1 & lt; x & lt2
So the value range of x is (-1, 2);
(2)
When m & lt=0, f (x)
When m>0, f (x)
When x belongs to, the range of (x 2-x+ 1) is, so m
So the range of m is (-infinity, 6/7).