When m=0, f (x) =-6.

When-2 < = m <; 0，x2-x+ 1 >； 0, so f (x) < 0;

When 0

x^2-x+ 1<； 6/2

(x-2)(x+ 1)& lt； 0，- 1 & lt； x & lt2

So the value range of x is (-1, 2);

(2)

When m & lt=0, f (x)

When m>0, f (x)

When x belongs to, the range of (x 2-x+ 1) is, so m

So the range of m is (-infinity, 6/7).