Proposition p: equation a? x？ +ax-2=0 has a solution on [- 1, 1].

Equation (ax+ 1/2)? = 2+ 1/4->； Solution: x 1 = 1/a, x2 =-2/a.

If p is a true proposition,-1

If p is a false proposition,-1

Q: Only one real number X satisfies the inequality X? +2ax+2a≤0

x？ +2ax+2a=0 Only equiroots, x? +2ax+2a=(x+a)？ -a？ +2a

-a？ +2a = 0->； A=0 or a=2

That is, when a=0 or a=2, the proposition q is true.

If q is a false proposition, a! =0 and a! =2

If the proposition "p or q" is false,->; Answer! =2,

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If the propositions "p and q" are true propositions, a=2.

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If the propositions "p and q" are false propositions,->; ，- 1 & lt； a & lt0，0 & lt； a & lt 1