Proposition p: equation a? x? +ax-2=0 has a solution on [- 1, 1].
Equation (ax+ 1/2)? = 2+ 1/4->; Solution: x 1 = 1/a, x2 =-2/a.
If p is a true proposition,-1
If p is a false proposition,-1
Q: Only one real number X satisfies the inequality X? +2ax+2a≤0
x? +2ax+2a=0 Only equiroots, x? +2ax+2a=(x+a)? -a? +2a
-a? +2a = 0->; A=0 or a=2
That is, when a=0 or a=2, the proposition q is true.
If q is a false proposition, a! =0 and a! =2
If the proposition "p or q" is false,->; Answer! =2,
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If the propositions "p and q" are true propositions, a=2.
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If the propositions "p and q" are false propositions,->; ,- 1 & lt; a & lt0,0 & lt; a & lt 1