B. Dilution with water promotes the hydrolysis of acetate ions, but does not change the hydrolysis equilibrium constant;
C, mixing the solution ① and the solution ② in equal volume, and just reacting to generate acetic acid and sodium sulfate, and analyzing and judging the existence of charge conservation in the solution;
D, at 25℃, the PH=7 of the mixed solution is 7, and the solution is neutral, which is judged according to the analysis of charge conservation in the solution;
A, solution ① is a strong alkali and weak acid salt solution, and acetate ions are hydrolyzed into alkalinity, which promotes the ionization of water; Solution ② is an acidic solution, which inhibits the ionization of water; At the same temperature, the ionization degree of water in solution: solution ① > solution ②, so A is wrong;
B. Dilution with water promotes the hydrolysis of acetate ions, but does not change the hydrolysis equilibrium constant; In solution
c(CH3COOH)？ C (oh? )
c(CH3COO？ ) unchanged, so b is wrong;
C, the solution ① and the solution ② are mixed in equal volume, and just react to generate acetic acid and sodium sulfate, the solution is acidic, and there is charge conservation analysis and judgment in the solution; [na+]+[H+]=[OH-]+[ch3coo-]+2 [so42-], if c[CH3COO-]+2[SO42-]=[Na+] gives [h+] = [oh-], the inconsistent solution is acidic; So, c is wrong;
D, at 25℃, the PH=7 of the mixed solution is 7, the solution is neutral, and there is charge conservation in the solution; [na+]+[H+]=[OH-]+[ch3coo-]+2 [so42-], [h+] = [oh-], c[CH3COO-]+2[SO42-]=[Na+] in the solution.
So choose D.
,6,(20 12? Jinan No.2 Model) Regarding the following two solutions, the correct one is ().
Solution ①: 0.2 mol? L-1 CH 3COONa solution;
Solution ②: 0. 1 mol? L-1H 2SO 4 solution.
A. At the same temperature, the ionization degree of water in solution: solution 1C (SO 4 2-).