And lim x→0+, f(x)= 1.
lim x→ 1-,f(x)=sin 1
According to Cantor's theorem, f(x) is uniformly continuous.
Similarly, when x is in the range of (-1, 0), f(x)=-sinx/x is a continuous function.
And lim x→0-, f(x)=- 1.
lim x→- 1-,f(x)=-sin 1
According to Cantor's theorem, f(x) is uniformly continuous.
When 0