And lim x→0+, f(x)= 1.

lim x→ 1-，f(x)=sin 1

According to Cantor's theorem, f(x) is uniformly continuous.

Similarly, when x is in the range of (-1, 0), f(x)=-sinx/x is a continuous function.

And lim x→0-, f(x)=- 1.

lim x→- 1-，f(x)=-sin 1

According to Cantor's theorem, f(x) is uniformly continuous.

When 0