Because Party A and Party B played four games each, and Party C was the referee for three times, indicating that Party A VS Party B played three games.

A VS B Every time you play, one person must leave (C play) and the other person will continue to play. It is impossible to play A VS B for two consecutive games. However, Party A and Party B always played only four games, and the two sides played against each other with three games. The other game must have been played with Party C, so Party C played two games, which happened to be twice between three times.

To sum up, the order of the five games must be: A vs. B, A (or B) vs. C, A vs. B, B (or A) vs. C, and A vs. B. Obviously, in the second game, C must have lost.

This question should be regarded as a logical question-# ~ If you don't understand anything, you can ask me ~Q402066937