(1) Complete the following statistics according to the polyline statistical chart.
(2) In the first half of 2006, the average monthly precipitation in a certain place was millimeters.
(3) The precipitation in June is more than that in April 10%.
(4) According to the statistical diagram, please put forward another parallel solution to the mathematical problem.
Test center: fill in the statistical chart; Single broken line statistical chart; Get information from statistical charts.
Analysis: According to the statistical chart, the precipitation from June to June is 10 mm, 30 mm, 45 mm, 50 mm, 35 mm and 60mm； respectively;
Complete the statistics and the following questions according to these data.
A: (1) The statistical table is as follows:
(2)(20+30+45+50+35+60)÷6,
=240÷6,
=40 (mm);
A: The average monthly precipitation in the first half of 2006 was 40 mm. 。
(3)(60-50)÷50,
= 10÷50,
=20%;
A: The precipitation in June is 20% more than that in April.
(4) Question: What percentage is the precipitation in February more than 1 month?
Answer:
(30-20)÷20,
= 10÷20,
=50%;
A: The precipitation in February is 50% more than that in 1 month.
So the answer is: 40, 20.
Comments: The key to this kind of problem is to look at the statistical chart and the data in the chart, and then find useful data to solve it according to the problem.