Assuming that the number of faces of this odd-numbered dice is n, the probability of throwing each face is equal, that is, 1/n, then the probability of throwing an odd number is (p 1 = (n+ 1)/2)/n, and the probability of throwing an even number is (p2 = (n-/kloc-).

When m such dice are thrown together, we can calculate the number of odd sums in all possible situations, thus finding out the probability that the sum of all dice throwing results is odd:

When m is odd, the sum of any m odd numbers is still odd, so the probability that the sum of all dice results is odd is 1.

When m is even, the odd sum must be composed of even odd numbers or even odd numbers, so the number of odd sums is c (m, 0) * c (m- 1, p2) m+c (m, 2) * c (m- 1, p2) (m-2) * p.

To sum up, when m odd dice are thrown together, the probability that the sum of all dice throwing results is odd is:

When m is odd, the probability is1;

When m is even, the probability is c (m, 0) * c (m- 1, P2) m+c (m, 2) * c (m- 1, P2) (m-2) * p 1 2+ ...

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