Practical application of permutation and combination. Special topic: calculation problems. Analysis: according to the meaning of the question, the sum of the numbers is 10, with 4,4, 1,1; 4,3,2, 1; 3,3,2,2; Then, the number of permutations in each case is worked out in turn, and addition principle is added to get the answer. Solution: When the sum of numbers is 10, there are 4,4, 1,1; 4,3,2, 1; 3,3,2,2;

When the card numbers are 4, 4, 1, 1; There are 44 different arrangements;

When the card numbers taken out are 3, 3, 2 and 2; There are 44 different arrangements;

When the card number is 4, 3, 2,1; There are two different ways to take each number, and there are 24A44 and 44 different arrangements.

So * * * has 2A44+2A44 = 18A44 = 432 different arrangements. Comments: This question examines the application of arrangement. When solving the problem, pay attention to whether the number may come from one card or two cards.