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There are two problems in the math exercise book of the second semester of Grade 8: Exercise 2 1.7( 1).
1 Solution: Suppose the price of each children's wear is reduced by X yuan, then the profit of each piece is: (40-X), and it can be sold every day: (20+8*x/4), that is, (20+2x).

Therefore, (40-X)(20+2x)= 1200 is simplified as 2x 2-60x+400 = 0, and the solution is x= 10 or 20, so every children's wear should be reduced.

Price 10 yuan or 20 yuan.

2 Solution: Suppose * * * there are x people going to the scenic spot, then the per capita travel expenses are:1000-20 (x-25) =1500-20x, because the per capita travel expenses are not allowed.

Lower than 700 yuan, so1500-20x > 700, so x

* * * Travel expenses paid to travel agencies: (1500-20X)X=27000, that is, 20x 2- 1500x+27000 = 0, x=30 or.

45 and x

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