3Y-2Z = 1→ 15y- 10z = 5②

7X+5Z = 19/4→ 14x+ 10z = 19/2③

②+③:

14x+ 15y=29/2 ④

14×①-4×④:

66y = 1 10→y = 1 10/66 = 5/3

Substituting y=5/3 into 3Y-2Z= 1 gives:

3×5/3-2z = 1→2z = 3×5/3- 1 = 4→z = 2

Substituting z=2 into 7X+5Z= 19/4 gives:

7x+5×2 = 19/4→7x = 19/4-5×2 =-2 1/4→x = 7×(-2 1/4)=-3/4

The solution of the equation is:

x=-3/4

y=5/3

z=2