∴∠ACD+∠DCE=∠BCE+∠DCE，

∴∠ACE=∠DCB，

And ∵CA=CD and CE=CB,

∴△ACE≌△DCB.

(2)△AMC∽△DMP。

Reason: ∫△ACE?△DCB,

∴∠CAE=∠CDB，

And ≈AMC =∠DMP,

∴△AMC∽△DMP.

(3)∫△AMC∽△DMP，

∴MA:MD=MC:MP.

And ≈DMA =∠PMC,

∴△AMD∽△CMP，

∴∠ADC=∠APC.

Similarly, BEC = BPC.

CA = CD，CB=CE，

∴∠ADC= ( 180 -∠ACD)，

∠BEC= ( 180 -∠BCE)。

∫∠ACD =∠BCE，

∴∠ADC=∠BEC，

∴∠APC=∠BPC.

That's all. That's enough, my friend.