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On-line solution of junior high school mathematics problems
1. According to the non-negative nature:

a- 1=0,b+ 1=0

That is, a = 1 and b =- 1.

Then a2009+b2010 =12009+(-1) 2010 =1+0 = 2.

2. 1※2= 1^2 -2= 1- 1=- 1

(- 1)※3=(- 1)^2-3 = 1-3=-2

Therefore, (1※2) ※3=-2

3. According to the non-negative nature:

x- 1/2=0,y+5=0

That is, x = 1/2 and y =-5.

-2x^3-y^2

=-2*( 1/2)^3-(-5)^2

=- 1/4-25

=- 10 1/4

4. Meaning: ab= 1, c+d=0.

Because |x|=2

So x2 = (| x |) 2 = 2 2 = 4.

Original formula = (-AB) 2009-3 (C+D)+(X 2) 2.

=(- 1)^2009-3*0+4^2

=- 1+ 16= 15

Reading: minus twenty-six plus eleven minus seven plus ten.

Also read: minus twenty plus eleven plus minus seven plus ten.