First of all, I don't understand why you connect the capacitor between the live wire and the ground wire. If you connect this capacitor, the live wire will form a loop with the ground through the capacitor, and of course there will be current through the capacitor. The magnitude of this current should be the voltage between the live wire and the ground wire (close to 220V) divided by the capacitive reactance of the capacitor at 50HZ, and the current is capacitive (the current leads the voltage by nearly 90 degrees). Of course, the current itself cannot pass through the capacitor. Capacitors are constantly charged and discharged in the AC circuit with the change of AC voltage, which feels like current is flowing. If this capacitor is connected, a leakage protector will trip, because the capacitor current is similar to the "leakage current" at this time. The larger the capacitance, the smaller the capacitive reactance and the larger the current. Capacitance current = voltage/capacitive reactance across the capacitor. (capacitance = 1/2πfC). Will it be forgotten?