PQDC is a parallelogram,
∴PD=QC,
PD=AD-AP=24-t,
QC=3t,
∴24-t=3t, and the solution is: t = 6;;
2.① Same as above: PQDC is parallelogram.
∴PD=QC,PD=AD-AP=24-t,
QC=3t, ∴24-t=3t, and the solution is: t=6.
② Quadrilateral CDPQ is isosceles trapezoid:
The PH⊥BC in h exceeds p, and the DE⊥BC in e exceeds d,
PQCD is an isosceles trapezoid,
∴PQ=DC,∠PQH=∠DC,
∵PH⊥BC,DE⊥BC,∴∠PHQ=∠DEC=90
* in △PHQ and △1February.
∠PQH=∠DCE, ∠PHQ =∠ dirk, PQ=DC,
∴△PHQ≌△DEC(AAS),
∴HQ=CE,CE=BC-AD=26-24=2,
HQ=QC-PD-CE=3t-(24-t)-2=4t-26,
4t-26=2,t=7。
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