Mathematical problems. Ask experts for answers ~
We can imagine that there are only x coconuts in the last pile. And it is the minimum number that meets the requirements, then the number of coconuts when the fifth person gets up is x/4 * 5+1=1.25x+1. When the fourth person gets up, the number of coconuts is1.25 (1.25x+1)+6550. X+ 1.25+ 1 You1.25 (1.25 (1.25x+1)+1The third person gets up = (/. 8 and 3 = 0.20703125+0.0517578125 x = k = > x = k/0.0517578125-4 = > K. Original coconut 8.20703125+3.0517578125x = 3121.