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With regard to similar triangles's question, P 104 14 is given in Qidong Ninth Grade Mathematics.
Solution: ∫∠B =∠B, ∠BEC=∠BDA.

∴ △BEC∽△BDA

∴ BD:BE=BA:BC

∴ △BDE∽△BAC

The area ratio is 2: 18.

The similarity ratio is 1:3.

∴ AC=3DE=6

∴ Height on the side of AC = 2×△ Area of ABC ÷AC=6