The first condition is: AC=90km.

The second condition is: AB=76.2km

Check:

The first conclusion is easy and omitted (45 points for the police and 54 points for the thief)

The first conclusion:

The distance a of the capture point d is AD=89.8km

The thief ran for 76.2/ 100 hours before it rained.

The police ran away (76.2/100-160) *120 = 71.44km,

The thief ran another 89.8-76.2= 13.6km, and it took 13.6/80=0. 17 hours.

The police ran 89.8-71.44 =18.36 km and spent18.36/108 = 0.17 hours.

The conclusion is correct.