Honey, five! =5*4*3*2* 1= 120 The answer is correct.

Let's set up five types of computers for ABCDE and five schools for A, B, C, D and E.

A school can get one of five modes, and there are five choices.

School b can get one of the remaining four options after choosing a, and there are four ways to choose.

School C can get one of the remaining three items after choosing A and B, and there are three options.

After choosing A, B and C, Party D can get one of the remaining two modes, and there are two ways to choose.

E school can get one of the remaining 1 items after four choices of A, B, C and D, and can have 1 options.

So the answer: 5! = 120