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Mathematics problems in eighth grade
(1)AN is in triangle ACN and BM is in triangle BCM. Using the triangle edge method, because ACM ACM and CBM are equilateral triangles, AC = cm, ∠ ACN = ∠ BCM = 120, CN=BC, and the two triangles are congruent, AN=BM is obtained.

(2)CE is in the triangle CEN, CF is in the triangle CFB, ∠ NCE = ∠ NCB = 60, CN=CB, ∠CBM=∠CNA (given by congruent triangles in the first question), so the two triangles are congruent and CE=CF is obtained.