1 Because the sum of the inner angles of a polygon can be divisible by 180, the remainder of 2000 divided by 180 is 20.

So this outer angle is 20 degrees.

Because the sum of the outer angles of the polygon is equal to 360 degrees, it can be assumed that this is an N-polygon with 180(N-2)=4*360.

Solution: N= 10

So this is a polygon of 10.

The sum of the outer angles of a polygon is 360 degrees, and the sum of the inner angles can be divisible by 180.

So the sum of all angles can also be divisible by 180, and the integer part of 1350 divided by 180 is 7.

So the sum of all angles of this polygon is 180*7.

Suppose this is an n-polygon, then there is

180(N-2)+360= 180*7

180N= 180*7

N=7

So it is a heptagon.

Because the sum of the inner angles of a polygon can be an integer of 180, and each inner angle is less than 180 degrees.

So the sum of the interior angles of this polygon is the minimum value that is greater than 2750 and divisible by 180, and the integer part of 2750 divided by 180 is 15, so this interior angle is180 *16-2750 =/kloc.