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Mathematical simulation questions for senior high school entrance examination
Solution: (1) e (2,2k+b), F(( 1-b)/k,1)

(2) The point where point B falls on the edge OA is B', so BB' is perpendicular to the straight line Y = KX+B.

Let the equation of a straight line be y'=(- 1/k)x+c, and the straight line can be solved by passing through points b (2, 1) and b' (a, 0).

a=k+2

BE=B'E, that is, (k+2-2) 2+(2k+b) 2 = [1-(2k+b)] 2, and the equivalent relationship between k and b is obtained as follows:

k^2+4k+2b= 1

(3) If b= 1 1/8 is brought into the above relationship, we can get K =- 1/2, and K =-7/2 (excluding).

Substituting k and b into (1), we can get the coordinates of e and f: e (2,3/8) and F(3/4, 1).

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