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Solving inequality 4-5 in mathematics elective course.
( 1)

f(x)>=3

| x-3 |+| x-2 |+k & gt; =3

|x-3|+|2-x| >=3-k

|x-3|+|2-x| >=|x-3+2-x|=|- 1|= 1

∴ 1>; =3-k

k & gt=2

(2)

k= 1

f(x)& lt; 3x

| x-3 |+| x-2 |+ 1 & lt; 3x

When x

3-x+2-x+ 1 & lt; 3x

x & gt6/5

∴6/5<; x & lt2

When 2

3-x+x-2+ 1 & lt; 3x

x & gt2/3

2/3 & lt; X< three

When x & gt=3 hours

x-3+x-2+ 1 & lt; 3x

x & gt-4

∴x>; =3

In a word, take the trade union as an example.

{ x | 6/5 & lt; X<2 or x & gt2/3}

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