∴x+y=0

∫2x-y = 2

∴y=2x-2

∴x+2x-2=0

∴3x=2

∴x=3/2

∴a=(3/2)？ =9/4

2. The solution of ∫ (root number 5) is: 2.236067 ... so the fractional part is: (root number 5)-2 = a.

The solution of ∵5- (root number 5) is: 2.7639320 ... so the fractional part is 5- (root number 5)-2.

=3- (radical number 5)=b

∴a？ -B? = [(root number 5)-2]? -[3- (root number 5)]?

=2 (radical number 5)-5

3. Hot ~ so tired

∫ The root numbers x+y- 1 and x-y+ 1 are reciprocal.

∴ root x+y- 1+ root x-y+ 1=0

The number in the root sign is always ≥0.

The sum of the two radical signs ∵ and ∵ is equal to 0.

So everyone is zero.

∴x+y- 1=0 x-y+ 1=0

∴x+y= 1 x-y=- 1

∴(x+y)2008+(x-y)20 10

= 1×2008+(- 1)×20 10

=-2

Detailed enough! ~

Can you get more ~ ~ ~ I'm exhausted.