The number of students in school A was originally 0/3 of that in school 65438+B. Later, school B transferred 20 students to school A. At this time, the number of students in school A is 3/5 of that in school B. How many students are there in school A and school B?

Solution:1÷ (1+3) =1/43 ÷ (3+5) = 3/8 20 ÷ (3/8-1/4) =/kloc-

160÷( 1+3)=40 (person) 40× 1=40 (person) 40×3= 120 (person)

A: there are 40 students in school A and 0/20 students in school B.

Analysis: Because in this problem, there are 20 more students in A school and 20 fewer students in B school. Therefore, the units before and after 1/3 are different from 3/5, so it cannot be directly calculated. However, there are 20 more students in school A and 20 fewer students in school B, and the total number of students in the two schools remains unchanged. Therefore, we can regard the total as the unit 1. It is concluded that the original number of students in a school accounts for 1/4 of the total number of students. After the transfer of 20 students, the number of students in school A is 3, and the number of students in school B is 5. At this time, the total number of students in the two schools is 8. At this time, the number of students in a school accounts for 3/8- 1/4 = 65438+.