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Mathematical spring to find the center of gravity
Let the distance between the center of the front and rear wheels of an automobile be L 1 and the horizontal distance from the center of gravity to the center of the rear wheel be L2, then

With the rear wheel as the rotating shaft, the force is balanced.

FL 1=GL2

L2 = fl1g = 6×103× 2104m =1.2m is obtained.

Then the horizontal distance from the center of gravity of the car to the center of the front wheel is l = 2m-1.2m = 0.8m..

Answer: The horizontal distance from the center of gravity of the car to the center of the front wheel is 0.8m 。