So ∠BCP=∠BPC

Because ∠α+∠BCP+∠BPC= 180

So ∠ α =180-∠ BCP-∠ BPC =180-2 ∠ BCP.

Because ∠ β+∠β+∠BCP = 90°

So ∠β=90-∠BCP.

So ∠α=2∠β.

Let me look at the second question, which has not been solved yet.