Let x 2-MX+2 = y, that is, x 2-MX+2-y = 0, and the interval 0, 1 has at least one zero point, so Dieta = m 2-8+4y is greater than or equal to 0.

Y is in the range of 0, 1.

0 & lt=4- 1/4m^2<； = 1

solve

2 root number 3

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