Similarly, f (-1) = KF (1) =-K.

(2)∫f(x)= KF(x+2)∴f(x+2)=f(x)/k

So f(2) to f(3) can be replaced by f(0+2) to f( 1+2).

That is, when x∈0, 1 is contained in 0,2, f (x+2) = f (x)/k.

So f(x+2)=x*(x-2)/k so f (t) = (t-4) (x-2)/kt ∈ 2,3.

That is, f (x) = (x-4) (x-2)/k x ∈ 2,3.

Similarly, when x ∈ 0,2, f(x)=x*(x-2).

F(x)=kx(x-2) when x ∈-2,0.

F(x)=k when x∈-3, -2? x(x-2)

Then according to the monotonicity of the derivative function, the player function is interesting.

(3) The extreme point is-2,0, 1.

Then compare f(-2), f(0), f(- 1), f(3) and f(-3).

Note: The above contents are copied.

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