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The average score of the final math exam in Class Two, Grade Five in a primary school is 90, with a total score of four digits A96B. How many students are there in this class?
Since A96B is a multiple of 90, so B=0, let n be the number of people, so:

1000*A+960=90*n, (a can only take 1, 2, 3, 4, 5, 6, 7, 8, 9),

n=( 100*A+96)/9，

N must be an integer, so 100*A+96 must be a multiple of 9.

Substitute 1, 2, 3, 4, 5, 6, 7, 8, 9 respectively, and after verification, it is obtained that only when A=3, n=396/9=44, it meets the meaning of the question, so the number of people is.

44 people.

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