The number abc is actually100a+10b+c.

Therefore, the sum of these five numbers can be represented by a, b and c as n =122a+212b+221c.

It is found that if a number abc is added, there is n+100a+10b+c = 222 (a+b+c), and the sum of n and the number abc is a multiple of 222. The number obtained by dividing 3 194 by 222 is greater than 14, so 3 194.

Try 3330, 3330-3 194= 136, that is, 15 times, but 1+3+6 is not equal to 15.

Try again 16 times, 3552-3 194=358, 3+5+8= 16.

If the multiples of 222 are calculated in advance before playing this game, as soon as you get n, you can immediately find the numerical calculus greater than n, and the effect will be faster and better.