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Fifth grade mathematics unit 5 trapezoidal area application problem
Hello, this question examines the calculation method of trapezoidal area.

(1) trapezoid area formula: (upper bottom+lower bottom) × height ÷2.

Let the height be x,

(2 1+45)×x÷2=759

66x÷2=759

33x=759

x=23

(2) If you haven't learned how to solve equations, go and learn them.

Or according to the trapezoid area formula: (upper bottom+lower bottom) × height ÷2.

Height =759÷[(2 1+45)÷2]

=759÷33

=23

His height is 23 meters.