1, from parabola y=2(x-m)? The vertex of +n is located in the fourth quadrant, m >；; 0，n & lt0.

The linear function y=mx+n does not pass through two quadrants.

2. let y = ax 2+bx+c.

Substitute ABC three points to get three equations.

0=9a+3b+c

6=c

16=a-b+c

The solution is a=2, b=-8 and c=6.

After the formula Y = 2 (x-2) 2-2, Y = 2x 2-8x+6.

So the symmetry axis is x=2, the vertex coordinate is (2,-2), and the other intersection point of the X axis is (1, 0). Because the two intersections are symmetrical about the symmetry axis, it is known that one is 3 and the other is 1.

3. Linear function of k >; 0 passes through one or three quadrants. Less than 0 passes through two or four quadrants. . . The other quadrant is determined according to the size of b, which is greater than 0 above the X axis and less than 0 below the X axis. . .

Then k and b pass through the first, second and third quadrants when they are greater than 0, and pass through the first, third and fourth quadrants when k is greater than 0 and b is less than 0. . .

Both k and b are less than 0, k is less than 0, and b is greater than 0. You can try to draw a picture and understand it yourself. . .

The linear functions k>0, y increase with the increase of x. . You can compare the pictures yourself, from left to right. . . X is increasing, pay attention to whether the image is rising or falling at this time, and the decline is decreasing. Rising is increasing, and the rest is understood by image. . . It's all words. I can only read it myself, but I can't understand it.