If the number in brackets is 0, then 20( )0( )0( )43/999=200200.243.

If you take all 9 and get 20( )0( )0( )43/999=209300.243, the multiple is A, then the number of A is between 200200 and 209300.

27 * 37 * a = (1000-1) * a =1000a-a = 20 () 0 () 43, and the last two digits of a are 57, which makes the last two digits of the number 43.

The verification value is 200257,999 * 200257 = 20056743.

Therefore, the last two digits of A between 200200 and 209300 are 57.

And because the fourth last digit of 20( )0( )0( )43 is 0, then the third digit of A is 6 (because the first last digit of A is 0, it can only be 7-6), and the fourth digit of 20 () 0 () 43 is also 0, and the fourth digit of A can only be 2 (because the first digit of A is 2, and A

Verification 206257*999=206050743

The three unknowns are 6, 5 and 7.