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Three math classes
Solution: (1) As shown in the figure,

* * * There are six situations, and the probability that the math class is arranged in the last section =; (2) As shown in the figure,

The curriculum arrangement of two classes, any arrangement of class (1) cannot correspond to all arrangements of class (2),

So * * * has 6×6=36 cases,

There are six situations in each combination, two of which conflict in math class and the other four do not.

Therefore, there are 4×6=24 cases without conflict.

The probability of no conflict in math class is: =.