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Senior two writes college entrance examination mathematics.
There are three situations that can be solved:

1. Boy A is on the left of the three boys. At this time, the other two boys had a 2/2 arrangement. A There must be a group of girls on the left. The girls are divided into two groups and ranked among the boys, so there is A2/2 * (C2/3 * A2/2) * C1/2 * C1/3 = 70.

There are 72 kinds of the same boys.

3. Among the three boys, team A has A2/2 (C2/3 * A2/A) * A2/4 =144.

So there are 288 kinds of * * *