Is that what you mean?

The answer is as follows:

Because a 2 = 4

So 2a=4

We can get | f 1m |+f2m | = 2a = 4 from the properties of ellipse.

(| f1m |+| f2m |)/4 =1-① formula

(1| MF1|+1| mf2 |) * ① formula

=1/4 (2+| MF1| mf2 |+| mf2 |/MF1|) ≥1/4 * 2+1/2 =/kloc-

So the minimum value is 1.

You can ask if you don't understand. I took the same test today, but it's www in Pudong New Area.

& gt