How to find the area of the shadow part to do the math problem of the sixth grade in primary school - Training Enrollment Network

How to find the area of the shadow part to do the math problem of the sixth grade in primary school

Shaded area = semicircle area with diameter 8+semicircle area with diameter 6+right triangle area-semicircle area with diameter 65438 +00.

The area of a semicircle with a diameter of 8 is 4×4×π÷2=8π.

The area of a semicircle with a diameter of 6 is 3×3×π÷2=4.5π.

The area of a right triangle is 6×8÷2=24.

The area of a semicircle with a diameter of 10 is 5×5×π÷2= 12.5π.

Shadow area =8π+4.5π+24- 12.5π=24 cm2.

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