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Seek the answer and explanation of the sixth grade math problem of Beijing Normal University! Urgent! ! ! ! ! ! ! ! !
Suppose that when A is half the age of B, A is one year old, B 2×A is old, and C 38 is old; When A is 17 years old, it is noted that the age difference between A and B is unchanged, so B is 17+a, so C is twice that of B, which is 2×( 17+a). According to the age difference between A and C, we can get: 38-A = 2× (65438+A). B is 14 years old, C is 38 years old, and the total is 7+ 14+38=59 years old, (113-59) ÷ 3 =18. In 18 years, the sum of their ages will be 60.
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