Therefore, when x→2 or x→-2, f(x)→∞

(2) When | 1-x|=0, x= 1.

When x→ 1, f(x)→-∞

When x→∞, f(x)→+∞

(3)- 1/x is the exponent of e, so when-1/x tends to +∞, f(x)→∞

At this point, x→0-

(4) Let the denominator √(x-5)=0 and x=5.

x-5 & gt； 0

Therefore, when x→5+, when f(x)→∞