1 1, Xiaoming and Xiaohua each have a few dollars, and Xiaoming has more money than Xiaohua by 85 yuan. After they both went to 30 yuan, Xiaoming had twice as much money left as Xiaohua. How much money do they each have?

Solution: Let Xiaohua have one yuan, then Xiaoming has a +85 yuan.

According to the meaning of the question

(a-30)×2=a+85-30

2a-60=a+55

A= 1 15 yuan.

Xiao Mingyou 1 15+85=200 yuan.

12. There is a rectangle. If its length and width are increased by 8 cm, its area will increase by 208 cm 2. It is known that the length of the original rectangle is 6 cm longer than the width. What is the area of the original rectangle?

Solution: if the width is a, then the length is a+6 cm.

Just draw it and you will know.

8a+8*(a+6)+8*8=208

8a+8a+ 1 12=208

16a=96

A=6 cm

Length = 6+6 =12cm

Area = 12×6=72 cm2.

13, A and B *** 140 yuan, A bought a book and used up 4/7 of his money. At this time, the money left by the two is the same. How much did Party A and Party B originally have?

Solution: Take the amount of armor as the unit 1.

Then the money brought by B is 1×( 1-4/7)=3/7.

So a originally had140/(1+3/7) =140/(10/7) = 98 yuan.

B The original money was 140-98=42 yuan.