As shown in the figure, extend AE through BC extension line to G.

Transverse e is BC vertical line.

EH:GH= 1:2 can be easily obtained from similarity.

(Shadow length: rod length = 2: 1)

And because ∠ ech = 30 and CE=2EH.

CE=4M

EH=2M

Similarly, CH=2√3M, GH=2√3M.

(CE:CH= 1:(√3)/2)

BG=4+2x√3/2=4+√3