BC=√[40？ +(8√3)? ]= 16√7

Ship speed =16 √ 7/(4/3) =12 √ 7 km/h.

(2) In the coordinate system as shown in the figure.

B(-20，20√3)C( 12，4√3)

Let a straight line lbc: y = kx+b.

Substitute the coordinates of b and c into y = kx+b.

Get -20k+b=20√3。

12k+b=4√3

The solution is k =-3/2 b =10 √ 3.

∴ Linear LBCY =-3/2x+10 √ 3

When y=0, x=20 is E (20,0).

∫M( 19.5，0)，N(20.5，0)

If the ship continues to sail and does not change its course, it can directly dock in MN.