Geometric proof in senior high school mathematics elective course
Because cd is parallel to ab and the angle aob is opposite to the angle cod, the cod of triangle is like aob of triangle.
Get cd/ab= od/ob.
cd/ab+ 1=od/ob+ 1
(cd+ab)/ab=(od+ob)/ob
(cd+ab)/ab=bd/ob
(8+6)/8= 15/ob
ob= 15*8/ 14=60/7
od= 15-ob=45/7