∠∠ACB = 90°

AB=2，AC=√2

∴BC=√[2^2-(√2)^2]

=√2

∴BC=AC

∴ Triangle ACB is an isosceles right triangle.

Angle BAC = 45

Connecting BD

Triangle ABD is a right triangle.

∫AD = 1，AB=2？

∴ Angle abd = 30

∴ Angle bad = 90°-30° = 60°.

∴ Angle CAD = 45+60 = 105

One side is alternating current, the other side is alternating current.

Similarly,

∠CAD=60 -45 = 15