Let the specified time be x.
80*[X-6]=50*[X+3]
X=2 1
Then the distance from home to school in Xiao Qiang is 50 * [2 1+3] = 1200m.
Method 2:
When Xiao Qiang advances at a speed of 50m, the distance from his school is 50 * 3 =150m at the appointed time.
If Xiao Qiang advances at a speed of 80 meters, if he continues to advance when he arrives at the school, then the distance beyond the school at the specified time is 80*6=480 meters.
Then the specified time is: [480+150]/[80-50] = 21minute.
Then the distance from home to school is 50 * [2 1+3] = 1200m.