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Ask a math problem in primary school
Xiao Qiang goes to the Children's Palace from home. If he walks 80 meters per minute, he will arrive six minutes earlier than scheduled. If you walk 50 meters per minute, you will be three minutes late. How far is Xiao Qiang's home from the Children's Palace?

Let the specified time be x.

80*[X-6]=50*[X+3]

X=2 1

Then the distance from home to school in Xiao Qiang is 50 * [2 1+3] = 1200m.

Method 2:

When Xiao Qiang advances at a speed of 50m, the distance from his school is 50 * 3 =150m at the appointed time.

If Xiao Qiang advances at a speed of 80 meters, if he continues to advance when he arrives at the school, then the distance beyond the school at the specified time is 80*6=480 meters.

Then the specified time is: [480+150]/[80-50] = 21minute.

Then the distance from home to school is 50 * [2 1+3] = 1200m.