Let's compare the power of 16 with the power of 18.
16^ 18- 18^ 16=( 16^9+ 18^8)( 16^9- 18^8)
16 9+ 18 8 is definitely greater than 0, and whether it is greater than 0 depends on 16 9- 18 8.
16^9- 18^8=(4^9+ 18^4)(4^9- 18^4)
4^9- 18^4=(2^9+ 18^2)(2^9- 18^2)
2^9- 18^2=32* 16- 18* 18>; 0
So 16 18-1816 > 0, that is, the power of18 of16 is greater than that of18.