1.

According to the CBD = 90, EDG angle = HDB angle = 30, BD = 9m.

HD=BD*2/ 1.73 and HB=BD/ 1.73 were obtained.

Get HC=HB+BC.

Because sunlight is parallel, which is AE//CD.

That can get HD/DE=HC/AC.

According to the data obtained above, only AC in this ratio is unknown and can be obtained.

2. According to the parallel relation, it can be concluded that △HDC is similar to △HEA.

In this way, the proportional relationship of their areas is the square of the proportional relationship of their sides.

S△HDC/S△HEA=(HD/HE=HC/HA)^2

The first question can find the ratio of sides, and the area of △HDC is S△HDC=S△BCD+S△HDB.

△BCD and△△△ HDB are right triangles, so it is easy to find the edge when you know it.

Then bring S△HDC into the above proportional relationship to get S△HEA.

The area of trapezoidal ACDE =S△HEA-S△HDC.